Question

A IS THREE TIMES AS OLD AS B TODAY AND A WAS FOUR TIMES AS OLD AS B THREE YEARS AGO . THEN WHAT IS THE SUM OF THEIR PRESENT AGES?

Answer 1

Answer:

the correct answer is 2A=7B

Answer 2

Step-by-step explanation:

let present age of B be x

present age of A=3x

3 years ago:

age of A=3x-3

age of B=x-3

ATQ,

3x-3=4(x-3)

3x-3=4x-12

4x-3x= -3+12

x=9

present age of B =9 years

present age of A=3x=3*9= 27 years

therefore,

sum of their present ages=9+27=36