A is three years older than B .A's father D is twice as old as A ; and B is twice old as his sister C the ages of C and D differ by 20 years . find the ages of A and B.
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Let the age of B = x and A will be x+2
D=2(x+2)=2x+4
C=x÷2
D-C=40 so 2x+4-x/2 = 40
4x+8-x=80
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3x=80–8
3x=72 so x =24 means B=24
A=26
D=52 (twice of A)
C=12(half of B) and D-C =52–12=40
Let the age of B = x and A will be x+2
D=2(x+2)=2x+4
C=x÷2
D-C=40 so 2x+4-x/2 = 40
4x+8-x=80
Please mark as brainliest
3x=80–8
3x=72 so x =24 means B=24
A=26
D=52 (twice of A)
C=12(half of B) and D-C =52–12=40
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