A is thrice as efficient as B and hence completes a work in 40 days less than the number of days taken by B. What will be the number of days taken by both of them when working together?
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Answer:
15 days
Step-by-step explanation:
Since A is three times more efficient than B, if A completes a work in x days, then B can complete the same work in 3x days.
It is also given that A can complete a work in 40 days less time than B, that is,
3x−x=40
⇒2x=40
⇒x= 40/2
⇒x=20
And, 3x= 3×20 =60
This means that when B can complete the work in 60 days, A can complete it in 20 days. So, both can together finish the work in:
20×60
---------
20+60
= 1200/80
=15 days.
Hence, both A and B can complete the work in 15 days.
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