A is thrice as good as work man B and together they finish a piece of work in 15 days. In how many days will A alone finish the work
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The ratio of their efficiencies = A:B = 3:1
Again it's given that they are able to do the whole work in 15 days. This means in one day they can do 1/15th of the work.
Let's get back to the ratio of their efficiencies again which is 3:1. It means if of A does 3 units of a work in a day then B does 1 unit of work. They together thus as per the ratio do 4 units of the work which is equal to 1/15th of the work.
4 = 1/15
1 = 1/60
Then 3 = 3×1/60= 1/20.
so 1/20 is the efficiency of A. This means A completes 1/20th of the work in a day meaning he will complete the work in 20 days. --- Answer
If you have any doubts, let me know.
Again it's given that they are able to do the whole work in 15 days. This means in one day they can do 1/15th of the work.
Let's get back to the ratio of their efficiencies again which is 3:1. It means if of A does 3 units of a work in a day then B does 1 unit of work. They together thus as per the ratio do 4 units of the work which is equal to 1/15th of the work.
4 = 1/15
1 = 1/60
Then 3 = 3×1/60= 1/20.
so 1/20 is the efficiency of A. This means A completes 1/20th of the work in a day meaning he will complete the work in 20 days. --- Answer
If you have any doubts, let me know.
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