Question

A is thrice of B, B is twice of C, and C is four times of D. If D is equal to 54546. Find the value of A + B+ C+ D A+B+C+D.

Answer 1

Answer:

110086809948

Step-by-step explanation:

here's the thing,

A=3B

B=2C

C=4D

D=54546

therefore, C= 4 * 54546= 218184

B= 218184 * 2 = 436368

A= 3 * 436368 = 1309104

therefore, A+B+C+D*(A+B+C+D) = A+B+C+D*(2018202)

                                                     = 1963656 + 110084846292

                                                     = 110086809948