Question

A is
twice
AS
as old
as & five years
ago A's age was
three
times B's age. find their present ages.
​

Answer 1

Answer:

let age of B is x and A is y

given A is twice old as B

y = 2x .........(1)

and 5 years ago

A age was 3 times of B

y-5 = 3(x-5)

y-5 = 3x-15.......(2)

put 1 in 2

2x-5 = 3x- 15

-5+15 = 3x- 2x

10= x

theage of B is 10

then A is 2x = 20

y= 20