A is twice as efficient as B and B is twice as efficient as if A and B together complete a work in 4 days yhen C alone can complete the work in?
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Hope this help you........
Step-by-step explanation:
Let, C can do a work in x days
So, In 1 day c can work =1/x part of the work
B can do a work in x/2 days
So, In 1day B can work =2/x part of the work
A can do a work in x/4 days
So, In 1 day A can work =4/x part of the work
If A, B, C togetherly work then,
In 1day they can do the work
=(1/x)+(2/x)+(4/x)
=7/x of the work
So to complete the work working togetherly they need =x/7 days
Now according to the question,
x/7=4
x =28
Then c alone can complete the work in 28 days......
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