A is twice as efficient as b and can complete a job 30days before
b.in how much they can complete the job together?
Answers
Answered by
0
(15×45)/15+45=( 15+45)/60=45/4= 11¹/⁴
Answered by
5
If A does a job in 30 days, B will take 60 days to complete the same job. (Just for the sake of A completing it 30 days before B)
Job completed by A in 1 day=1/30
Job completed by B in 1 day=1/60
Job completed by them in 1 day together=2+1/60=3/60=1/20
let x be the days in which they complete the job
So,
x/20=1
x=20
So, while A was takng 30 days to complete a job and B was taking 60 days to complete the same job, together they can do it in 20 days.
Job completed by A in 1 day=1/30
Job completed by B in 1 day=1/60
Job completed by them in 1 day together=2+1/60=3/60=1/20
let x be the days in which they complete the job
So,
x/20=1
x=20
So, while A was takng 30 days to complete a job and B was taking 60 days to complete the same job, together they can do it in 20 days.
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