Question

A is twice as efficient as B and therefore is able to finish a job in 30 days less than B Working together, they can do it in

Answer 1

Answer:

20 days

Step-by-step explanation:

A is twice as efficient as B

i.e efficiency ratio of A : B = 2:1

efficiency is considered as one day work.

Number of days taken by A = (x-30) days

Number of days taken by B = x days

Total Work done by A = (x-30) * 2

Total Work done by B = x * 1

By equating work done

$( x - 30) \times 2 = x$

$x = 60$

Total Work done by A = 30 days

Total Work done by B = 60 days

$\frac{1}{30} + \frac{1}{60} = \frac{1}{20}$

Together they can do it in 20 days