A is twice as efficient as B and together they finish a project in 14 days. Find how many days will each require to do the same project individually
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Answer:
Let B take x days, then A takes x−12 days, but A is twice efficient than B, hence A will take half the time taken by B.
Hence, (x−12)=
2
1
x
∴2x−24=x
∴2x−x=24
x=24 days
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