A is twice as efficient as B. If time taken by B to complete 4/7 part of the work is 6 days more more than the time taken by A to complete 3/7 part of the same work. In how many
days can A alone do the work ?
Answers
Answered by
0
In three days, since a is twice efficient than b
Awinneet:
No this is not the answer. Other thing I would like to comment is that you can't solve a problem of mathematics without giving the procedure.
ok
Similar questions