Question

A is twice as efficient as B, who is thrice as efficient as C. If C alone can compete the task in 30 days, then in how many days can they together compete the task?​

Answer 1

$\blue{\bold{\underline{\underline{Answer:}}}}$

$\green{\tt{\therefore{Days=\frac{60}{11}\:days}}}$

$\orange{\bold{\underline{\underline{Step-by-step\:explanation:}}}}$

$\green{\underline\bold{Given :}} \\ \tt: \implies C \:can \:done \: a \: work \: in \: 30 \: days \\ \\ \red{\underline\bold{To \: Find:}} \\ \tt: \implies In \: how \: many \: days \: they \: complete \: the \: work = ?$

• According to given question :

$\bold{As \: according \: to \: relation \: given} \\ \\ \text{A \: is \: twice \: effective \: than \: B}\\ \tt: \implies 2A = B \\ \\ \tt: \implies A = \frac{B}{2} - - - - - (1) \\ \\ \text{a \: is \: thrice \: effective \: than \: c}\\ \tt: \implies 3A = C\\ \\ \tt: \implies a = \frac{B}{3} - - - - - (1) \\ \\ \text{From \: (1) \: and \: (2)} \\ \tt: \implies \frac{B}{2} = \frac{c}{3} \\ \\ \tt: \implies B = \frac{30 \times 2}{3} = 20 \: days \\ \\ \green{\tt: \implies B\: can \:complete \: the \: same \: work \: in \: 20 \: days} \\ \\ \text{putting \: value \: of \: B\: in \: (1)}\\ \tt: \implies A = \frac{20}{2} = 10 \: days \\ \\ \green{\tt: \implies A \: can \: complete \: the \: same \: work \: in \: 10 \: days} \\ \\ \bold{For \: together \: work: } \\ \tt: \implies One \: day \: work = \frac{1}{10} + \frac{1}{20} + \frac{1}{30} \\ \\ \tt: \implies One \: day \: work = \frac{6 + 3 + 2}{60} \\ \\ \tt: \implies One \: day \: work = \frac{11}{60} \\ \\ \green{ \tt{\therefore In \: \: \frac{60}{11} days \: they \: complete \: the \: work}}$

Answer 2

Step-by-step explanation:

hey guys please refers this attachment

( ◜‿◝ )♡Pranay0144