Question

A is twice as efficient as C & B is 50% more than that of C and both work on a task for (x+4) days and (x+20) days respectively. If remaining 90/7% of the work complete by C in 18 more days with the efficiency of 2 units/days .Find out what portion of work will be completed in x days.if all three work together?

Answer 1

Step-by-step explanation:

Let B take x days, then A takes x−12 days, but A is twice efficient than B, hence A will take half the time taken by B.

Hence, (x−12)=

2

1

x

∴2x−24=x

∴2x−x=24

x=24 days