Math, asked by jyotijoshi216, 11 months ago

A is twice as fast as B and B is thrice as fast as c. if B takes 18 minutes to cover a certain distance, find the difference in the time taken by A and C to cover the same distance

Answers

Answered by hafiz023

HEY MATE

A=2B

B=3C=>C=B/3

given B=18

C=18/3=6

A=2B=2*18=38

A-C=38-6=32

I HOPE THIS WILL HELPS U.....

hafiz023: mark it as brainlist

Answered by greatyu

Answer:63

Step-by-step explanation:IF A IS 12 THEN B WILL BE 24 THEN C WILL BE 72.

SO 18X3=54.

18 DIVIDED BY 2 TO FIND THE VALUE OF A=9.

SO 54+9=63.

ANSWER 63.

PLZ MARK THE BRAINLIEST.

greatyu: sorry but it is 54-9=45 so a will be 45

jyotijoshi216: still have some doubt can u explain it more

hafiz023: yeah

greatyu: b=18 a is twice so 9 +9 = 18 a =9 b=18 thrice will be multiplied to get the value of c so 18x3 54. to make it equal 54-9=45. so 54-45 or 9

greatyu: or 9+45 will be equal

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