A is twice as good a workman as B & together they finish a piece of work in
16days. A alone can finish the work in *
O 28days
21 days
024days
O 36days
Answers
Answered by
0
Answer:
Together they complete the work in 18 days
So, in one day they complete 1/18 work.
Since A is twice good as B
So A's workdone in one day= 2x
& B's workdone in one day= x
So, 2x + x = 1/18
3x = 1/18
X = 1/54
So, B's workdone in oneday= 1/54
& A's workdone in one day= 1/27
So, A alone will take 27 days to complete a piece of work
Ans: 27 days
Answered by
0
Answer:
27 days
Step-by-step explanation:
Together they complete the work in 18 days
So, in one day they complete 1/18 work.
Since A is twice good as B
So A's workdone in one day= 2x
& B's workdone in one day= x
So, 2x + x = 1/18
3x = 1/18
X = 1/54
So, B's workdone in oneday= 1/54
& A's workdone in one day= 1/27
So, A alone will take 27 days to complete a piece of work
Ans: 27 days
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