Math, asked by punisha6904, 10 months ago

A is twice as good a workman as b and therefore is able to finish a job in 50 days less than b

Answers

Answered by RvChaudharY50
10

Answer:

A:B = 2:1 (Efficiency)

A:B = 1:2 (Time)

it is given that time difference = 50 days .

so,

A:B = 50 : 100 (Time)

Now , you didn't write what we have to get ,

let me guess , in how many days they both complete the work ?

since LCM of 50, 100 = 100 = Total work ,

Both do the job in = 100/(1+2) = 100/3 = 33(1/3) days .

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