A is twice as good a workman as b and therefore is able to finish a job in 50 days less than b
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Answer:
A:B = 2:1 (Efficiency)
A:B = 1:2 (Time)
it is given that time difference = 50 days .
so,
A:B = 50 : 100 (Time)
Now , you didn't write what we have to get ,
let me guess , in how many days they both complete the work ?
since LCM of 50, 100 = 100 = Total work ,
Both do the job in = 100/(1+2) = 100/3 = 33(1/3) days .
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