A is twice as good a Workman as B and they were together finish of a piece of work in 10 days find the number of days taken by each to finish the work.
(solve by using unitary method)
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Step-by-step explanation:
A does 1/x amount of the work while B does 1/2x amount in the same time. Together they do 1/x + 1/2x = 3/2x amount in the same time. So the time taken to complete the job is 2x/3 = 18. So x = 3*18/2 = 27. So A would take 27 days and B 54 days to do the same job, working alone.
Check: 1/x + 1/2x = 1/27 + 1/54 = 2/54 + 1/54 = 3/54. So time taken be both working together is 54/3 = 18 days. Correct.
B requires 54 days.
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