A is twice as good a workman as b and together they finish a piece of work in 18 days.In how many days will a alone finish the work.
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Answer:
A=27 days, B= 54 days
Step-by-step explanation:
Let work done by B in 1 day = x
Then, work done by A in 1 day = 2x
Therefore, work done by A and B in 1 day => x+2x=3x
Given, A and B can finish the work in 18 days
=> Work done by A and B in 1 day = 1/18
=> 3x=1/18
=> x=1/(18×3)
x= 1/54
Therefore, B alone can finish the work in 54 days
A alone can finish the work in 27 days
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