Question

A is twice as good a workman as B and together they finish a piece of work in 14 days.In how many days can A alone do it.​

Answer 1

Answer:

$the \: answer \: is \: 21$

Answer 2

Answer:

Let the work done by B be x.

∴Work done by A =2x

Work done by A and B together in 14 days =1

Work done by A and B together in 1 day =

$\frac{1}{14}$

Work done by A in 1 day + Work done by B in 1 day =

$\frac{1}{14}$

$x + 2x = \frac{1}{14} \\ 3x = \frac{1}{14} \\ x = \frac{1}{42} \\ Work \: done \: by \: B \: in 1 \:  day = \frac{1}{42} \\ ∴ Work \: done \: by \: A \: i n  \: 1 day = \frac{1}{21} </p><p>$

Hence, to finish the work, A require 21 days.

Hence, A alone can finish the work in 21 days.