Question

A is twice as good as workman as B and together they finish a piece of work in 20 days. In how many days will A alone finish the work?

Answer 1

let B takes x no. of days to finish a work
then A will take 2x days to finish that work
according to question,
x+2x=20
3x=20
x=20/3 days
2x=20*2/3
=40/3 days
therefore, A can complete that work in 40/3 days. Ans

Answer 2

HEY FRIEND HERE YOUR ANSWER

Let B be x and A be 2x

(A+B)'s 18 days' work=1

(A+B)'s 1 days' work=1/18

This can also be written as

x+2x=1/18

3x=1/18

x=1/54

Let's multiply both sides of this equation by 2.
Therefore,

2x=1/27=>A's 1 day's work=1/27

Thus, A alone can do a piece of work in 27 days.


I HOPE IT'S HELP YOU

MARK BRAINLIEST MY ANSWER DEAR FRIEND

THANKS... .