Question

A is twice as old as; 5 years ago he was three times as old;​

Answer 1

Correct Question

A is twice old as B. Five years ago A was 3 times as old as B. Find their present ages.

Solution :-

A's age = a; B's age = b

A's age = a; B's age = b ∴ 2b = a . . . . (1)

; a − 5 = 3(b − 5)

=> a = 3b − 1 . . . . (2)

=> 2b = 3b − 10

=> b = 10 years

10 yearsand a = 2b = 2 × 10 = 20 years