Question

A is twice as old As B. 10 years ago A was 7 times as old as B find their present ages​

Answer 1

Step-by-step explanation:

Let the present age of B = x years

Therefore, age of A = 2x years

Ten years ago:

Age of A = (2x - 10) years

Age of B = (x - 10) years

According to the given condition:

(2x - 10)=7(x - 10)

2x - 10 = 7x - 70

70-10= 7x - 2x

60 = 5x

$\therefore \: x = \frac{60}{5} \\ \therefore \: x =12 \\ \implies \: 2x = 2 \times 12 = 24 \\ thus \: \\ present \: age \: of \: A = 24 \: years \\ present \: age \: of \: B = 12 \: years$