Question

A is twice as old as



b. 12 years ago, a was five times as old as



b. find the present age of



a.

Answer 1

let the age of B be x
age of A=2x
before 12 years;
age of B=x-12
age of A=5(x-12)=5x-60
value of X=)5x-60=2x-12
=)5x-2x=60-12=)3x=48=)x=48/3=)x=16
present age of B=16
present age of A=32

Answer 2

Answer:

The present age of B is 16 years and A is 32 years.

Step-by-step explanation:

Given A is twice as old as B.

And 12 years ago, A was five times as old as B.

Let the age of B be $B$ years.

Then the age of A is $2B$ years. i.e., $A=2B$                         ...(1)

Thus 12 years ago, the age of B was $B-12$ years and  of A was $A-12$ years

But given 12 years ago, the age of A is 5 times of B.

This can be written as $A-12=5(B-12)$

Substituting the value of A from equation (1),

$2B-12=5(B-12)$

$\implies 2B-12=5B-60$

$\implies 60-12=5B-2B$

$\implies 3B=48\implies B=\dfrac{48}{3}=16$

Then the age of A is $2B=2\times 16=32$

Hence, the present age of B is 16 years and A is 32 years.