A is twice as old as B, 3 year ago A was three times as old as B. how old is A now?
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Answered by
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Answer:
Step-by-step explanation:
At present,
A = 2B ………(1),
3 years ago,
(A - 3) = 3 × (B - 3),
A - 3 = 3B - 9,
A - 3B = -6,
2B - 3B = -6………[∵ from (1) A = 2B],
B = 10,
If B = 6 then from (1) A = 12,
Present age of A = 12 years,
Present age of B = 6 years.
Hope it helps you.
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