Math, asked by sidmugal2, 8 months ago

A is twice as old as B, 3 year ago A was three times as old as B. how old is A now?​

Answers

Answered by ItzArmaanSarao
1

Answer:

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Answered by Itzraisingstar
0

Answer:

Step-by-step explanation:

At present,

A = 2B ………(1),

3 years ago,

(A - 3) = 3 × (B - 3),

A - 3 = 3B - 9,

A - 3B = -6,

2B - 3B = -6………[∵ from (1) A = 2B],

B = 10,

If B = 6 then from (1) A = 12,

Present age of A = 12 years,

Present age of B = 6 years.

Hope it helps you.

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