Question

A is twice as old as B 5 years ago A"s age was 3 times b,s age .what is the present age

Answer 1

Answer:

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Answer 2

Answer:

Let age of B be x

Therefore age of A=2x

Age of A 5 years ago=2x-5

Age of B 5 years ago=x-5

Age of A 5 years ago=3 times age of B 5 years ago

2x-5=3*(x-5)

2x-5=3x-15

2x-5+15=3x

2x+10=3x

10=3x-2x=x

Present age of A=2x

                            =2*10

                            =20

Present age of A is 20 years