A is twice as old as B; 5 years ago he was three times as old; what are their present ages?
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Explanation:
Let, the age of B be x and the age of A be 2x.
Hence, 5 years ago B was three times as old.
According to the sum,
2x - 5 = 3 ( X - 5 )
=> 2x - 5 = 3x - 15
=> 3x - 2x = 15 - 5
=> X = 15 - 5
=> X = 10.
Age of A is 2X ,.i.e., 2×10 = 20 years ; age of B is X ,.i.e. 10 years. ( ANS )
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