A is twice as old as B. After 8 years the sum of their ages will be 28 years. Find there present ages
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Answers
Answer:
Step-by-step explanation:
A said to B: "I am twice as old as you were when i was as old as you are." Sum of their current age is 49.
Let present age of A be x years, so present age of B is 49 - x
Age difference between A and B
= x - (49 -x)
= 2x - 49
when A's age was 49 - x, B's Age must be leader by their age difference According
B's earlier age = (49 - x) - (2x - 49)
49 - x - 2x + 49
= 98 - 3x
As per statement A said to B: "I am twice as old as you were when i was as old as you are
Thus A's present age is twice that of B's earlier age:
x = 2 (98 - 3x)
x = 196 - 6x
x + 6x = 196
7x = 196
x = 196/7
x = 28
Thus, A's current age is 28 years.
As sum of their present ages are 49 years therefore B's age
= 49 - 28 = 21 years
A's present age is 28 years and B's present age is 21 years.
Answer A's present age is 28 years and B's present age is 21 years.