Math, asked by Manashvee, 1 year ago

a is twice as old as b . eight years ago a was thrice as old as b . what are the present ages of a and b

Answers

Answered by littyissacpe8b60
0

a = 2b

8 years ago

a's age = a - 8

b's age = b - 8

ie.  a - 8 = 3(b-8)

2b - 8  = 3b - 24

b  = 16

a = 2 x 16 = 32

a's age = 32

b's age = 16

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