Question

A is twice as old as b five years ago A's age was three time's B's age fing the present age​

Answer 1

Answer:

A is 20 years old and B is 10 years old.

Step-by-step explanation:

Let,

The present age of B = x

The present age of A = 2x

Five years ago,

The age of B = x - 5

The age of A = 2x - 5

Also,

A's age was three time's B's age

★ According to the Question :

⇒ 3 (x - 5) = 2x - 5

⇒ 3x - 15 = 2x - 5

⇒ 3x - 2x = - 5 + 15

⇒ x = - 5 + 15

⇒ x = - 5 + 15

⇒ x = 10

The present age of B = 10 years

___________________________

The present age of A = 2x

⇒ 2 (10)

⇒ 20

The present age of A = 20 years

Therefore, A is 20 years old and B is 10 years old.