Question

A is twice as old as B five years ago A was 3 times as old as B find their present age

Answer 1

A=2B.............(1)
A-5=3(B-5)........(2)
By putting value of A from 1 to 2
2B-5=3B-15
-5+15=3B-2B
10=B
Putting value of B in 1
A=2(10)
A=20
Age of A=20years
Age of B=10years.



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Answer 2

here now, age of A=2×age of B.....(1)
five years ago,
age ofA (a-5 )=3×(b-5)age of B
a-5=3b-15
so a=3b-10
put in 1
a=2b
3b-10=2b
B=10 years.
a=20 years(2b)