"A" is twice as old as "B" five years ago his age was three times "B" age. Find the present age
nikhilroy27:
let the age of B 5 years ago be x so,age of A be 2x present age of B=ox
let the age of B 5years ago be xso, age of A be 2x now present age of B= x+5 andA=2x+5 a/q 2x+5=3 (x+5) 2x+5=3x+15 x=15-5=10
age of B=10 and age of A=2×10=20
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Answer:
Step-by-step explanation:
A=2B...........eq1
Before five years
A-5=3(B-5)
A-3B=-10............eq2
eq1-eq2=
B=10 years
A=2×10
A=20years
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