Math, asked by Internationareader, 1 month ago

'A'is twice as old as 'B' Four years ago A's age was three
times B's age. The present age of A is
(a) 8 years (b) 10 years (c) 14 years (d) 16 years.
4​

Answers

Answered by hindustanipoet
0

Answer:

The present age of A is 16 years.

Step-by-step explanation:

Given,

A = 2B ... present situation

A - 2B = 0 .... (1)

A - 4 = 3(B - 4) .... 4 years ago

A - 3B = -8 .... (2)

Subtracting (2) from (1)

B = 8

Therefore,

A = 16

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