Question

A is twice as old as B.If in 18 years A will be 5/4 times as old as B will be then. find B's present age​

Answer 1

Answer:

Step-by-step explanation: see the attachment

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Answer 2

B present age is 6 years

Step-by-step explanation:

• Given that

        Present age of B = k

        Present age of A = 2 k     (Given)

• After 18 years, age of A and B will be

        After 18 years age of B = k + 18

        After 18 years age of A = 2 k + 18

• It is given that after 18 years A will be 5/4 times as old as B. Means

        $\mathbf{\frac{2\ k+18}{k+18}=\frac{5}{4}}$

• On cross- multiplication, we get

        4( 2 k + 18) = 5( k + 18)

        8 k + 72 = 5 k + 90

        8 k - 5 k = 90 - 72

        3 k = 18

• So

         k = 6

• Then

         Present age of B = k = 6 years

         Present age of A = 2 k = 2× 6 = 12 years