Question

A is twice as old as B. Ten years ago he is 4 times old as B. What are their present age?

Answer 1

Answer:B is 15 , A is 30

Step-by-step explanation:

Let B's age be x years. Then A's age is 2x years.

Ten years ago, their ages were, respectively, x-10 and 2x -10 years. Thus, we have

2x−10=4(x−10)

or 2x−10=4x−40

or 2x=30

∴x=15

So, B is 15 years old and A is 30 years old.

PLS MARKS AS BRAINLEST