Question

'A' is twice as old as 'B'. Three year ago 'A
was three times as old as 'B'. How old is 'A'
now?
​

Answer 1

Answer:

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Answer 2

Consider B’s present age as x years. So age of A is 2x years. 3 years ago, B’s age was (x-3) years, and A’s age was (2x-3)years. The equation for the age relation 3 years ago is,

3 B’s age = A’s age.

So, 3(x-3)= 2x -3.

3x-9 = 2x - 3.

x = 6.

So, B’s age is 6 years. And as A is twice as old as B at present.

Therefore, A’s present age is 12 years