A is twice efficient as B. A and B together do the same work in as much time as C and D can do together. If the ratio of the number of alone working days of C to D is 2:3 and if B worked 16 days more than C then no of days which A worked alone? A. 18 Days B. 20 Days C. 30 Days D. 36 Days
Answers
Answered by
0
Answer:
20 Days
Step-by-step explanation:
Time Taken by A = x days
Time Taken by B = 2x days
Time Taken by C = 2y days
Time Taken by D = 3y days
It is given that B works 16 days more than C
2x-2y = 16 --------------------> Eqn 1
It is also given that A+B = C+D
x+2x = 2y+3y
=> 3x = 5y ---------------------> Eqn 2
Solving 1 and 2, we get x = 20 and y = 12.
So, A takes 20 days.
Similar questions