Question

A is twice good as workman as B and together they finish a piece of work in 18 days in how many days A will alone finish the work​

Answer 1

Answer:

Let the work done by B be x.

∴Work done by A =2x

Work done by A and B together in 14 days =1

Work done by A and B together in 1 day =

14

1

⇒ Work done by A in 1 day + Work done by B in 1 day =

14

1

x+2x=

14

1

⇒3x=

14

1

⇒x=

42

1

Work done by B in 1 day =

42

1

∴ Work done by A in 1 day =

21

1

Hence, to finish the work, A require 21 days.

Hence, A alone can finish the work in 21 days.