Question

a is twice good as workman as the b and together they finish a piece of work on 18days . in how much days will b alone can finish that work​

Answer 1

Step-by-step explanation:

Together they complete the work in 18 days

So, in one day they complete 1/18 work.

Since A is twice good as B

So A's workdone in one day= 2x

& B's workdone in one day= x

So, 2x + x = 1/18

3x = 1/18

X = 1/54

So, B's workdone in oneday= 1/54

& A's workdone in one day= 1/27

So, A alone will take 27 days to complete a piece of work

Ans: 27 days

Answer 2

Answer:

27 days

Step-by-step explanation:

Together they complete the work in 18 days

So, in one day they complete 1/18 work.

Since B is twice good as A

So B's work done in one day= 2x

& A's work done in one day= x

So, 2x + x = 1/18

3x = 1/18

X = 1/54

So, A's work done in one day= 1/54

& B's work done in one day= 1/27

So, A alone will take 27 days to complete a piece of work

Ans: 27 days

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