Question

a is twice odd as b.5 years ago ,a was 3 times as odd as b.find their present age

Answer 1

Answer:

The answer is 10yrs and 20yrs respectively.

Step-by-step explanation:

Let age of B is x

Then age of A is 2x

5 years ago A is 3 times as old as B.

5 years ago the age of A was (2x-5)

Similarly 5 years ago age of B was( x-5)

According to the question, 2x-5=3(x-5)

2x-5=3x-15

x=10 yrs

So, present age of B is x i. e 10 yrs and present age of A is 2x=2×10=20 yrs

hope it helps

Answer 2

Answer:

Age of A=4 years and age of B=2 years

Step-by-step explanation:

Let the age of B be x years.

So, age of A = 2x years

Before 5 years,

Age of A = (2x-5) years

Age of B = (x-5) years

According to the question,

x-5=3(2x-5)

=>x-5=6x-15

=>6x-x=15-5

=>5x=10

=>x=2 years

So, age of A = (2×2) years

= 4 years

Hope it helps......

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