Question

A is twice of B . 5 years ago his age was 3 times B's age find their present age​

Answer 1

A = 2 ×B

A=3×B-5

that become,2×B=3×B-5

2×B-3×B= -5

-B=-5

5 years ago B's age is 5 then A's age is 3 times of B .

then 5×3 =15

after 5 year age of A is twice of B

then B's age = 5+5=10

then A's age =twice of B =10×2=20