Question

A is twice old as B . 10 year ago A was 4 times as old as B. what is the present age of A​

Answer 1

Answer:

A=2B

10byrs ago,

A-10=4(B-10)

2B-10=4B-40

30=2B

B=15

SO,A=2*15=30 YRS

Step-by-step explanation:

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Answer 2

Answer:

B=15 A=30

Step-by-step explanation:

Let B's age be x years. Then A's age is 2x years.

10 years ago, their ages were , respectively, x-10 and 2x - 10 years. Thus we have:-

2x-10=4(x-10).

2x-10=4x-40

2x=30

therefore x=15

so, B is 15 years old and A is 30 years old