A is twice old as B. 5 years ago A was 3 times as old as B .find their present ages
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let present age of B be x and that of A is 2x
a/q
3(x-5) =(2x-5)
3x-15=2x-5
x=10
therefore present age of A be 20 year and that of B be 10 year
a/q
3(x-5) =(2x-5)
3x-15=2x-5
x=10
therefore present age of A be 20 year and that of B be 10 year
sharjeel2:
thank u very much
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