Question

A is twice old as B. 5 years ago.A was 3 times old as B. find their present ages​

Answer 1

Step-by-step explanation:

Let the present ages of A and B be x and y respectively.

5 years ago,ages were x-5 and y-5

x = 2y

x-5=3(y-5)

2y-5=3y-15

15-5=3y-2y

10=y

x=2*10

x = 20

Therefore Present age of A is 20 and Present age of B is 10.

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