Question

A is twice old as B. Five year ago A was 3times as old as B. Find their present age

Answer 1

Solution:-
Let age of A be x.
And age of B be y.

x=2y.....(1)

A/q

$= > (x - 5) = 3(y - 5) \\ = > x - 5 =3y - 15 \\ = > x - 3y = - 15 + 10$
By putting value of x,from (1) equation we get,
$= > 2y - 3y = - 10 \\ = > - y = - 10 \\ = > y = 10$
Hence,
Age of B is 10years
Age of A is 20 years