A is twice old as B. five year ago A was B times as old as B find their present age
Answers
Answered by
0
Let A's age be x years.
B's age be y years.
ATQ,
x=2y...(i)
Five years ago,
x-5=3(y-5)
x-5=3y-15
x-3y-5+15=0
x-3y+10=0
x-3y= -10...(ii)
Substitute value of x in (ii)
2y-3y=-10
-y=-10
y=10.
Substitute value of y in (i)
x=2(10)
x=20.
Hence, the age of A is 20 years while the age of B is 10 years.
HOPE IT HELPS U...
B's age be y years.
ATQ,
x=2y...(i)
Five years ago,
x-5=3(y-5)
x-5=3y-15
x-3y-5+15=0
x-3y+10=0
x-3y= -10...(ii)
Substitute value of x in (ii)
2y-3y=-10
-y=-10
y=10.
Substitute value of y in (i)
x=2(10)
x=20.
Hence, the age of A is 20 years while the age of B is 10 years.
HOPE IT HELPS U...
Similar questions