Question

A is twice old as B. Five years ago A was 3 times as old as 8. Find their present age​

Answer 1

Answer:

Let age of B is x

Then age of A is 2x

5 years ago A is 3 times as old as B.

5 years ago the age of A was (2x-5)

Similarly 5 years ago age of B was( x-5)

According to the question, 2x-5=3(x-5)

2x-5=3x-15

x=10 yrs

So, present age of B is x i. e 10 yrs and present age of A is 2x=2×10=20 yrs