Question

A is twice old as B. Five years ago A was 3 times as old as B. Find their present ages.

Answer 1

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Answer 2

Answer:

A = 20 years,

B = 10 years.

Step-by-step explanation:

As per the question,

Let us say the age of B = x

So,

Age of A = 2x

Age of A, 5 years ago = 2x - 5

Age of B, 5 years ago = x - 5

So, from the given question we can say that,

(2x - 5) = 3(x - 5)

2x - 5 = 3x - 15

x = 15 - 5 = 10

x = 10 years.

Therefore, we can see that,

Age of B = 10 years.

and,

Age of A = 20 years.

Therefore, the present age of A and B are 20 and 10 years respectively.