Question

A is twice old as B. Five years ago A was
3 times as old as B. Find their present ages.​

Answer 1

Answer:

here is the answer

Step-by-step explanation:

Let the age of B is x

Then the age of A is 2x

5 years ago A is 3 times as old as B.

5 years ago the age of A was (2x-5)

Similarly, 5 years ago the age of B was( x-5)

According to the question, 2x-5=3(x-5)

2x-5=3x-15

x=10 yrs

So,the  present age of b is x i.e 10 years old and the present age of A is 2x=2*10 =20 years old

pls mark brainileist

Answer 2

Answer:

A=10 yrs old.

B=20 yrs old.

Step-by-step explanation:

• Let the age of B is x

• Then the age of A is 2x [A is twice old as B]

• 5 years ago A is 3 times as old as B.

• 5 years ago the age of A was (2x-5) [It is said that 5 years ago so 2x-5]

• Similarly, 5 years ago the age of B was (x-5) [It is asked 5 years ago so x-5]

• According to the question, 2x-5 = 3(x-5)

• So, 2x-5 = 3x-15

• x = 10 yrs [B = 10 yrs]

• So, the present age of b is 10 years old.

• So, 2x = 2 × 10 = 20

• The present age of A is 20 yrs.

Thank you,

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