Question

A is twice old as B.Five years ago A was 3 times as old as B. Find their present ages.

Answer 1

Here is your answer it may help...

Answer 2

Let the present age of B is y and Age of A be x.

Given that A is twice old as B.

= > x = 2y   -------------------- (1)

Given that five years ago A was 3 times as old as B.

= > x - 5 = 3(y - 5)

= > x - 5 = 3y - 15

= > 2y - 5 = 3y - 15

= > 2y = 3y - 10

= > -y = -10

= > y = 10.


Substitute y = 10 in (1), we get

= > x = 2y

= > x = 2(10)

= > x = 20.


Therefore the present age of A = 20 years and B = 10 years.


Hope this helps!