Question

A is twice old parts as B . Five years ago A was 3 times as old B. FIND THEIR PRESENT AGES

Answer 1

Answer:

let b present age = x

a present age =2 x

five years ago

b age = x-5

a age =2x-5

ATQ

3(x-5)= 2x-5

3x -15=2x-5

3x-2x = -5+15

x = 10

thetefore b age x=10 years

a age = 20 years