A is twice old parts as B . Five years ago A was 3 times as old B. FIND THEIR PRESENT AGES
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Answer:
let b present age = x
a present age =2 x
five years ago
b age = x-5
a age =2x-5
ATQ
3(x-5)= 2x-5
3x -15=2x-5
3x-2x = -5+15
x = 10
thetefore b age x=10 years
a age = 20 years
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